/* Collapse point is a running term defining the theoretical
distance an athlete's previous training has equipped them to
complete. This calculates what distance a runner should be
able to run based on his or her current mileage or how much
someone needs to run to complete a certain distance. */
#include <stdio.h>
#include <stdlib.h>
int main()
{
int choice, mpw, rd;
float miles_needed, cp;
puts("!!! Collapse Point Calculator !!!\n");
puts("\nCollapse point is a running term");
puts("defining the theoretical distance");
puts("an athlete's previous training has
equipped them to complete.");
puts("It states that a runner can complete
three times");
puts("his or her daily average before
they reach exhaustion.");
puts("\nEnter option 1 to find your
collapse point.");
puts("\nEnter option 2 to find out
how many miles you must run");
puts("per week for a given event.");
scanf("%d", &choice);
if(choice == 1)
{
system("CLS");
puts("You entered option 1.");
printf("Enter your weekly mileage: ");
scanf("%d", &mpw);
cp = (mpw/7)* 3;
printf("\nYour collapse point is
%.2f miles.\n", cp);
}
else
{
system("CLS");
puts("You entered option 2.");
puts("\nPick from the following
race distances:");
puts("1.) 5K (3.1 miles)");
puts("2.) 10K (6.2 miles)");
puts("3.) 10 Miles");
puts("4.) Half-marathon (13.1 miles)");
puts("5.) Marathon (26.2 miles)");
printf("\nEnter number of »
race distance: ");
scanf("%d", &rd);
switch (rd)
{
case 1:
printf("You must run %.2f miles »
per week to",
miles_needed = (3.1/3)*7);
printf(" comfortably finish a 5K.\n\n");
break;
case 2:
printf("You must run %.2f miles »
per week to",
miles_needed = (6.2/3)*7);
printf(" comfortably finish a 10K.\n\n");
break;
case 3:
printf("You must run %.2f miles »
per week to",
miles_needed = (10 / 3)*7);
printf(" comfortably finish »
a 10-mile race.\n\n");
break;
case 4:
printf("You must run %.2f miles »
per week to",
miles_needed = (13.1/3) * 7);
printf(" comfortably finish »
a half-marathon.\n\n");
break;
case 5:
printf("You must run %.2f miles »
per week to",
miles_needed = (26.2/3)*7);
printf(" comfortably finish »
a marathon.\n\n");
break;
default:
printf("You either run too much »
or not enough!!!\n");
}
}
system("PAUSE");
return 0;
}
:: Top ::
